naxko.blogg.se

It's counterintuitive, but you need to do the 'opposite formula' to get what you're looking for.

Don't try to calculate the chance of getting say heads in three flips, calculate the chance of NOT getting heads at all and then subtract that from 100% (or 1.00 probability). So for any one flip the chance of heads is 50%, so the chance of Not_Heads (tails) is 100%-50%=50%. So in two flips, to not get any heads you need the first flip no heads (50%) and then the 2nd flip no heads (50% again) so the probability of no heads in two flips is 0.5 * 0.5 = 0.25, the "one in four" of the iterated-out example (TT from ). So "the formula" that you get at least one of something in a series of trials is, where n is the number of flips or trials or whatever and probability_not is (1 - probability) of the event. #WOW MOUNT DROP CHANCE CALCULATOR EQUATION SERIES# #WOW MOUNT DROP CHANCE CALCULATOR EQUATION SERIES#.